Calculate the perimeter of ABCD.
B
+
6 cm
950
8 cm
5 cm
C

The perimeter is 28.13 cm

Step-by-step explanation:

We connect a line from A to C

we can use the cosine rule to find the length AC

let us call it x

AC^2 = AB^2 + BC^2 - 2(AB)(BC) cos B

we have this as;

x^2 = 6^2 + 8^2 - 2(6)(8) cos 95

x^2 = 36 + 64 + 8.37

x^2 = 108.37

x = √108.37

x = 10.4 cm

AC = 10.4 cm

now, let us look at triangle ADC Where we have AC as the hypotenuse as it is the side facing the right angle

We can use Pythagoras’ theorem to get the value of CD

We have it that the square of the hypotenuse AC is the sum of the squares of the two other sides

let DC be y

10.4^2 = 5^2 + y^2

y^2 = 108.37 - 25

y^2 = 83.37

y = √83.37

y = 9.13 cm

The perimeter of the shape is the sum of all its sides

so we have;

AB + BC + CD + AD

= 6 + 8 + 9.13 + 5

= 28.13 cm

angle addition postulate

2x=56

step-by-step explanation: