Solve the inequality x^2+ 3x-4 ≥ 0

Finding the roots of the given equation as shown below:

x

2

+3x−4>0

x

2

+4x−x−4>0

x(x+4)−1(x+4)>0

(x+4)(x−1)>0

Case-1:- Case-2:-

x−1>0 and x+4>0 x−1<0 and x+4<0

x>1 and x>−4 x<1 and x<−4

from above two we get from above two we get

x>1 …(1) x<−4 …(2)

From (1) and (2)

x lies between (−∞,−4)∪(1,+∞).

f(x) is the value of the function. b is the value of the function when x equals zero or the y-coordinate of the point where the line crosses the y-axis in the coordinate plane.

step-by-step explanation:

hope this !

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )