57:22 5 What is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the point (-4,-3)? 2 1 (-1, 1) 513 2 1 2 3 4 % Oy+3= -41%+4) Oy+3= *(** 4) Oy+3 = *(+4) Oy+ 3 = 4(x + 4) 0,-3) Mark this and return Save and Exit Next Submit

C. y + 3 = ¼(x + 4)

Step-by-step explanation:

✔️Find the slope of the given line:

Slope = ∆y/∆x = -(4/1) = -4

The line that is perpendicular to the given line on the graph would have a slope that is the negative reciprocal of -4.

Thus, the slope of the line that is perpendicular to the line on the graph would be ¼.

m = ¼.

Since the line passes through (-4, -3), to write the equation in point-slope form, substitute a = -4, b = -3, and m = ¼ into y - b = m(x - a)

Thus:

y - (-3) = ¼(x - (-4))

y + 3 = ¼(x + 4)

"exterior angles = 360 / number of sides.

60 = 360 / sides

sides = 360 / 60

sides = 6"