I will give brainliest if your answer is correct :) Let a = x^2 + 4. Rewrite the following equation in terms of a and set it equal to zero. (x^2 + 4)^2 + 32 = 12m^2 + 48 In resulting equation what is the coefficient of the a term? In the resulting equation, what is the constant?

Answers:

Work Shown:

Let's isolate x^2

a = x^2 + 4

x^2 + 4 = a

x^2 = a - 4

Then we'll apply substitution

(x^2+4)^2 + 32 = 12x^2 + 48

a^2 + 32 = 12x^2 + 48 replace x^2+4 with 'a'

a^2 + 32 = 12(a-4) + 48 replace x^2 with a-4

a^2 + 32 = 12a-48+48 distribute

a^2 + 32 = 12a

a^2 + 32 - 12a = 0

a^2 - 12a + 32 = 0

The last equation is in standard form.

The coefficient of the 'a' term is -12 since it is the number to the left of the 'a'. We don't focus on a^2 here.

The constant term is the term without any variable attached, so the constant is 32.

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.

a) one student is chosen from classroom a, then a student is chosen from classroom b.  

step-by-step explanation:

independent events are ones in which the probability of one event does not affect the probability of the second event.

one student is chosen from classroom a; this does not affect the chances of choosing a student from classroom b.   this makes these independent events.

when one card is chosen from a standard deck and then set aside before a second card is chosen, the probability of the second card being chosen changes.   this makes them dependent events.

when one student is chosen from classroom a and then a second student is chosen from classroom a, the probability of choosing the second student changes.   this makes them dependent events.

when a letter is chosen from the alphabet and then a second letter is chosen, the probability of choosing the second letter changes.   this makes them dependent events.