If p(x) = 2x2 – 4x and q(x) = x – 3, what is (p circle q) (x)? 2x2 – 4x + 12
2x2 – 16x + 18
2x2 – 16x + 30
2x2 – 16x + 15

2x^2 - 16x + 30

Step-by-step explanation:

Here, we want to get the composite function;

p•q(x)

All we have to do here is to replace the x value in p(x) by the totality of q(x)

we have this as ;

= 2(x-3)^2 - 4(x-3)

= 2(x^2 -6x + 9) - 4(x-3)

= 2x^2 -12x + 18 -4x + 12

= 2x^2 - 16x + 30

we know that

applying the law of sines

°

so

∠j=18°

∠k=29°

∠l=180-(18+29)=133°

the answer part a) is

the measure of angle k is  ≈29°

part b)  the measure of angle k could also be

(180-29)=151°

so

∠j=18°

∠k=151°

∠l=180-(18+151)=11°

the answer part b) is

the measure of angle k could also be 151°

read more on -

answer: -2+√x,-2-√x

i hope this , i don't know if you're looking for a pair or not.