PLEASE HELP!
graph the following equations: y=-4

A solid horizontal line across -4. I've attached a picture of the graph down below

Step-by-step explanation:

Since there is no independent variable (x) in the equation, the dependent variable does not change and stays the same.

In other words, no matter what x is, y will always be -4.

In picture form, that would be a solid horizontal line across -4, since slope is 0 and y is unchanging.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

step-by-step explanation: