How would i solve y=x+z/a-x and solve for x

Step-by-step explanation:

Making x the subject of the formula;

y=x+z/a-x

Cross multiply

y(a-x) = x+z

ya - yx = x+z

Collect like terms

x+yx = ya - z

x(1+y) = ya - z

x = ya-z/1+y

Hence the value of x is ya-z/1+y

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~

3 3 6, because in every triangle the longer side is always shorter than the sum of the other two