Given: Bis the midpoint of DC and 2D AZC Prove: ZEZA
D
E
B
STATEMENTS
1. Bis the midpoint of DC
2. DB BC
3. 2D2C
4. ABC 2 ZEBD
5. ABC AEBD
6. ZE ZA
REASONS
1. Given
2. Definition of Midpoint
3. Given
4.
5.
6.
Which of the following lists the missing reasons in the respective order?
Alternate Interior Angle Theorem, ASA, CPCTC
Vertical Anglo Thoorom, ASA, CPCTC
Linear Pair Postulate, SSS, CPCTC
Reflexive Property, CPCTC, AAS

it is contrapositive

i could not see the question too well so check yourself again too . this is because i want you to get it correct.

this linear equation would have just one solution.

step-by-step explanation:

the reason why this would have one solution is that it is an expression with just one variable. since that variable is not raised to a power, it will always have just one solution.

noncoplanar points are points that do not lie on the same line.

it would be r^2 - 2rs +s^2

assuming   you mean to square it