In the diagram below, DF = JL = a, FE = LK = b, and triangle DEF is a right triangle. Use the drop-down menus to complete the proof that if the equation a² + b2 = cis true of
the side lengths in triangle JKL, then triangle JKL must be a right triangle.

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

pi x^2

step-by-step explanation:

pi times x squared

p = 6s

step-by-step explanation:

b

step-by-step explanation: