CAN SOMEONE SOLVE BOTH OF THESE PROBLEMS ILL GIVE BRAINLIEST

1) HL=15

2)EF=23

Step-by-step explanation:

(I did the 2nd one first), , HL=21, EF=31

Step-by-step explanation:

FInd the midsegment of a trapezoid by adding the bases and dividing by two

(9x+3+5)/2=4x+7, now solve for x

9x+3+5=8x+14

x=6, so ef is 31

Do the first one the same way;

(2.5(12)+12)/2=HL

42/2=HL, HL=21

three-fourths of an hour

36÷48=0.75

0.75=

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet