PLEASE I NEED HELP FAST Jim and Pam's friend, Michael, saw how much fun they were having building rockets that he wanted to build one too. Michael wanted to
build a rocket that would fly higher than Jim and Pam's.
The friends decided to make it a contest and see who had the rocket that flew the highest. On the day of the launch, each team launched
their rocket while a computer recorded an equation that followed it's parabolic path, where y = the height of the rocket in yards and x = the
horizontal distance on the ground in yards. The results are in:
Jim and Pam's rocket had a path modeled by the equation: y = -5x^2+ 75x - 130
Michael's rocket had a path modeled by the equation: y = -5x^2 + 65x - 60
Who won the contest? That is, which parabola had the highest maximum height?
Explain your answer below using 2 different methods. (Choose from: a graph, table, and/or calculating the vertex). Remember, explain
your answer below and show work on your paper. You must explain/show your answer using 2 different methods.

Which statement best explains why ben uses the width hi to create the arc at j from point k

Determine if the following statement is true or false. the normal curve is symmetric about its​ mean, mu. choose the best answer below. a. the statement is false. the normal curve is not symmetric about its​ mean, because the mean is the balancing point of the graph of the distribution. the median is the point where​ 50% of the area under the distribution is to the left and​ 50% to the right.​ therefore, the normal curve could only be symmetric about its​ median, not about its mean. b. the statement is true. the normal curve is a symmetric distribution with one​ peak, which means the​ mean, median, and mode are all equal.​ therefore, the normal curve is symmetric about the​ mean, mu. c. the statement is false. the mean is the balancing point for the graph of a​ distribution, and​ therefore, it is impossible for any distribution to be symmetric about the mean. d. the statement is true. the mean is the balancing point for the graph of a​ distribution, and​ therefore, all distributions are symmetric about the mean.

Simplify 1/3 12x - 6 a. -2x-1 b.-2x-8 c.-x+4 d.3x+10 e. 4x-2