What are the solutions to the quadratic equation (round to nearest hundredth) x2 + 6x
-6 = 0 ?

x = 0.88 OR x = -6.88

Step-by-step explanation:

Given the quadratic equation: + 6x - 6 = 0

Applying the quadratic formula to determine the solutions, we have:

x = (-b ± ) / 2a

where; a = 1, b = 6 and c = -6

x = ( -6 ± ) / 2

  = ( -6 ± ) / 2

  = (-6 ± ) / 2

x = (-6 ± 7.75) / 2

So that,

x = (-6 + 7.75) / 2 OR x = (-6 - 7.75) / 2

x = OR

x = 0.88 OR -6.88

Thus, the solutions are: x = 0.88 OR x = -6.88

you have orange juice on wednesday. (idk why this is the answer)

step-by-step explanation:

in mathematics, a constraint is a condition of an optimization problem that the solution must satisfy. there are several types of constraints—primarily equality constraints, inequality constraints, and integer constraints. the set of candidate solutions that satisfy all constraints is called the feasible set.

hoped i'm right lol