What is the equation of the line perpendicular to x+2y=-6 through (6,-2) in standard form

y = 3 or  (0, 3)

Step-by-step explanation:

x + 2(0) - 6 = 0  

x + 0 - 6 = 0

x - 6 = 0  

x - 6 +6 = 0 + 6    (add 6 to both sides)

x = 6

The x-intercept is the point (6, 0)

On a graph, plot this point on the x axis.

Next we want to find the y-intercept. To do this we will set the x value to zero. -->

0 + 2y - 6 = 0

2y - 6 = 0

2y - 6 + 6 = 0 + 6 (add 6 to both sides)

2y =  6

2y/2 = 6/2  (divide both sides by 2)

y = 3

The y-intercept is the point (0, 3)

On the same graph, plot this point on the y-axis

b

step-by-step explanation:

1. 16.64

a^2+b^2=c^2

pr^2=pq^2+qr^2

pr^2=14^2+ 9^2

pr^2=196+81

pr= sqr root of 277

16.64

2. 11.31

c^2-a^2=b^2

18^2- 14^2=b^2

b^2=324-196

b=sqr root of 126

b=11.31

hope it ! (btw im in connections academy to, good luck! )