Which equation represents a functional relationship?.. Y=6

X=6
Plz justify your answer~

defines y as a function of x, because for every x value there is no more than a y value. (In fact for every x there is exactly one y value). We can forgive a function if some values of x do not have a y, but if there is more than one y for even one value of x, then the relation is not a function.

x=y2+6  does not define y as a function of x, because some value(s) of x have more than one y.

In general,

       x=y2-6--->x+6=y2

So, all the values of x larger than -6 would have two y values.

For example, x=10 would be paired with y=4 and y=-4.

A function cannot assign more than one y to any x value.

Step-by-step explanation:

i am not sure if this is what you mean tell me if it is not i will try one more time

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: