A cash register contains $10 bills and $50 bills with a total value of $1080. If there are 28 bills total, then how many of each does the register contain?

20 $50 bills

8 $10 bills

Step-by-step explanation:

Find how many $10 and $50 bills are in the cash register.

Make a systems of equations:

t = Amount of $10 bills

f = Amount of $50 bills

10t + 50f = 1080

t + f = 28

Lets solve for $50 bills first:

10t + 50f = 1080

-10(t + f = 28) = -10t - 10f = -280

Solve for f:

10t + 50f = 1080

-10t - 10f = -280

40f = 800

Divide both sides by 40.

f = 20

There are 20 $50 bills.

Now we need to find how many $10 bills are in the register.

Plug in 20 to "f" in one of the equations and solve for "t".

Solve:

t + 20 = 28

Subtract 20 from both sides.

t = 8

There are 8 $10 bills.

Your answer should be:

20 $50 bills

8 $10 bills

15 batches are the most you can make

step-by-step explanation:

the answer is 40.

proof: