The sum of the digits of a two digit number and the number reversed is 34. The difference of the number and the number with the digits reversed is 36. Find the original number.

original number: 62

Step-by-step explanation:

number: xy

(x+y) + (10y+x) = 34

2x + 11y = 34    (1)

(10x+y) - (10y+x) = 36

9x - 9y = 36

x - y = 4

x = y + 4

2* (y+4) + 11y = 34    (substitute (1))

13y + 8 = 34

13y = 26

y = 2

x = 6

Number: 62

step-by-step explanation:

im not sure what the answer is

let x and 400 - x be the two numbers.  

==> 0.80x + 0.85(400 - x) = 400 - 68 from the statement of the problem.  

< ==> 0.80x + 0.85(400 - x) = 400 - 68  

==> 340 - 0.05x = 332  

< ==> -0.05x = -8 ==> x = 160, the first number ==> 400 - x = 240, the second number.