Mathematics, 29.01.2021 02:40 andrew5632
1) During busy times, 60 potential customers per hour arrive at the booth (assume a Poisson distribution). A booth worker takes 3.75 minutes, on average, to meet the information needs of a potential customer (assume an exponential distribution). How many booth workers are required for the average potential customer to spend no more than 5 minutes waiting and being served
Answers: 2
= 16 customers per hour
= 3.75
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1) During busy times, 60 potential customers per hour arrive at the booth (assume a Poisson distribu...
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