Al, Bert, and Rob determined that the sum of their ages is 62. Bert is twice as old as Rob, who is 10 years older than Al. How old is each?

AI is 8, Rob is 18, and Bert is 36

Step-by-step explanation:

Ok, so the sum of their age is 62. Bert is x2 of Rob. Also someone is 10 years older than AI, lets assume Rob is the guy that is 10 years older. x+y+10+(z times 2)=62. So lets solve it. 62-10=52. 52=x+y+(z times 2). Now if you think about it x and y is the same, because the 10 is already minused. So it's now x*2+z*2=52, if you assume it now, z is x+10. So now it is 52=x*2+(x+10)x2. Now we break out the brackets so its x*2+x*2+20=52. Lets simplify it. x*4+20=52, lets swift the 20 the the other side. x*4=52-20, x*4=32. 32/4=8 so 8 is x. Now we know AI is 8, Rob is 18, and Bert is 36!

1. is 4 and 2. is 3

step-by-step explanation:

so if you look at the first one you see that 1 is to 4 and 2 is to 8 and so on, so you can see for every 1 there is a times 4 so if it were 3 then it would be 3*4 and it is 12

for number 2 it is 3 because 1 is to 3 and 2 is to 6 so for every 1 there is 3 so if it were 3 then there would be 3*3 = 9