Every year after a new car is purchased, it loses 1/3 of its value
(Depreciation). Let's say that the
new car costs $18,000. What is the
value of the car after 3 years?
Do you think this is a linear
relationship? Explain your
Reasoning

The value of car after 3 years is $5333

It is an exponential relationship.

Given :

Every year after a new car is purchased, it loses 1/3 of its value

one third of value is depreciated. So,

two third of the value is remaining after depreciation .

Let's say that the new car costs $18,000.

The value of cost of new car after 1 year is

Now again the car value is depreciated on second year

The value of cost of car after 2 years is

The value of cost of car after 3 years is

The cost of car after 'n' years is

Its an exponential relationship.

because 2/3 is multiplied 'n' times .

The value of car after 3 years is

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The value of the car after 3 years is $5,333.333

And no, the relationship is not linear, is an exponential decay.

Step-by-step explanation:

We know that every year, the car loses 1/3 of its value.

So if the initial value of the car is V.

After one year, the new value of the car will be:

Value (1 year) = V - (1/3)*V = (2/3)*V

After another year, the value will be:

Value (2 years) = (2/3)*V - (1/3)*(2/3)*V = V*(2/3)^2

Ok, we already can see that this is an exponential decay.

(So no, this is not a linear relationship).

The value equation as a function of the number of years will be:

Value(N) = V*(2/3)^N

Then if the initial cost of a car is $18,000, and we want to know its value after 3 years, we need to replace V by $18,000 and N by 3 in the above equation:

Value(3) = $18,000*(2/3)^3 = $5,333.333

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step-by-step explanation:

10/60

step-by-step explanation:

if you divide 10 by 60 the answer is 0.166666 while if you divide or solve the other problems it equals 0.6