Factor 2a5 b + 2a4b2+ 2a 3 b3.
2a²b(a2 + ab + ab)
2a3b(a2 + ab + b2)
2ab3a3 + ab + b2)

Here is your answer

The first one, i believe, would be correct. all the others have one thing in common, and that's that they have repeating numbers. in the second one, x and y have repeating 6's and 3's, and in the third, x and y have repeating 6's as well. in the last one, there are repeating 3's. the first one has no repeating numbers.

Socrat use det app ok