A number has the digits 6, 2, 9 to the nearest 100, the number rounds to 600 what is the number

This question is based on the concept of round - off rule. A number has the digits 6, 2, 9 to the nearest 100, the number rounds to 600  is 629.

Given:

A number has the digits 6, 2, 9 to the nearest 100, the number rounds to 600 what is the number.

According to the question,

The digit is given that 6, 2 and 9.

So, the digit at hundredth place is 6 and last two digit will be 29 or 92.

But, it is given that the number rounds to 600.

Thus, the number is at hundredth place is 6 and tenth place is 2 and at unit place is 9.

Therefore, the number would be 629 which is the number rounds to 600.

and the number 692 is not closest to 600.Thus we have to choose 29.

Hence, the number is 629.

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629

Step-by-step explanation:

rounds to 629 as t he closest hundred

b. 2

step-by-step explanation:

the slope of a line =δy/δx

δy= y₂-y₁

δx= x₂-x₁

therefore, using the points (-2,-3)   and (3,7) we can calculate gradient as follows:

m=(7--3)/(3--2) (a number minus a negative number the sign changes to a plus)

m=(7+10)/(3+2)

=10/5

=2

coin flip

non-answer:

choosing

sorry if this isnt what you're looking for i dont really understand the question