Write PQ−⇀− with P(2,−4) and Q(3,6) in component form.

1,10

Step-by-step explanation:

The initial point of the vector is P(2,−4) and the terminal point of the vector is Q(3,6).

Subtract the coordinates of the initial point from the coordinates of the terminal point.

PQ−⇀−=<xQ−xP,yQ−yP>

Substitute the coordinates of the given points.

PQ−⇀−=<3−2,6−(−4)>

Simplify.

PQ−⇀−=<1,10>

Therefore, the component form of vector PQ−⇀− is <1,10>.

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