A bag contains 4 sour-apple candies and 3 watermelon candies. One piece of candy is chosen at random and returned to the bag. Then a second piece of candy is chosen at random What is the probability that both pieces of candy chosen will be sour -apple ?

Step-by-step explanation:

Given: A bag contains 4 sour-apple candies and 3 watermelon candies.

Total candies = 4+3 = 7

If replacement of candy is done, then the probability of getting sour apple will be the same and independent each time .

Probability of selecting sour apple candy=

Now , the probability that both pieces of candy chosen will be sour -apple  =

hence, required probability =

b

2

−

b

b

3

+

7

b

2

+

14

b

+

6

%

−

3

b

3

+

7

b

2

+

14

b

+

6

%

step-by-step explanation: