What is the x-intercept of the line containing the points (–6, 10) and (12, –2)?

Well we have to know the equation of slope >  slope(m) = (y2 - y1) / (x2 - x1)
(-6,10) > find our which is the x coordinate in the first set of coordiantes >x1 = -6 and our y which is the first y or our first y int in our first set of coordinates > y1 = 10 
(12,-2) Same concept as the first set of coordinates, we are just find the second values now. >x2 = 12 > y2 = -2
Now we have to begin substituting!
slope(m) = 
slope(m) = 
slope(m) =  < We want to dwindle this as low as possible to get our slope!
slope(m) = 
Moving on we have to use y = mx + b now so we know slope(m) = -2/3 which leads us to choose any of your points however I will choose our first set (-6, 10) > x = -6 and y = 10
10 =
10 = 4 + b 
10 - 4 = b 
6 = b 
Now we know that our equation is >y = 
Let us find the x-intercept by subbing 0 in for y!
y = 
So just reduce the fraction and we get x = 9! This means our x-intercept is (9, 0)

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