\dfrac{3}{2}+(-k)+(-2) 2
3

+(−k)+(−2)start fraction, 3, divided by, 2, end fraction, plus, left parenthesis, minus, k, right parenthesis, plus, left parenthesis, minus, 2, right parenthesis where k = -\dfrac{5}{2}k=−
2
5

k, equals, minus, start fraction, 5, divided by, 2, end fraction.

bdhdisbdbxbxuxbdvzhzjzbz huh Bc vd

Step-by-step explanation:

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

none.

step-by-step explanation:

m

1

=

5

m1=5

b

=

−

1

b=-1

find the slope and y-intercept of the second equation.

tap for more

m

2

=

0

m2=0

b

=

−

6

b=-6

compare the slopes

m

m of the two equations.

m

1

=

5

,

m

2

=

0

m1=5,m2=0

compare the two slopes in the decimal form. if the slopes are equal, then the lines are parallel. if the slopes are not equal, then the lines are not parallel.

m

1

=

5

,

m

2

=

0

m1=5,m2=0