URGENT: A grocer has 150 kg of walnuts that sell for $6 per kg. She plans to add almonds that sell for $5.30 per kg to the walnuts to make a mixture that sells for $5.50 per kg. How many kg of almonds should she add? (MUST SHOW WORK)

let c = cashew pounds, w = walnut pounds, m = mixed pounds

Here's what we know:

c + w = m

7c + 5.5w = 6.50m

m = 35

So we now have:

c + w = 35

7c + 5.5w = 227.5

We can use substitution or elimination here. Let's try substitution in this case:

c = 35 - w

7(35 - 7) + 5.5w = 227.5

245 - 7w + 5.5w = 227.5

245 - 1.5w = 227.5

-1.5w = -17.5

w = 11 2/3

Now to solve for cashews:

c = 35 - 11 2/3

c = 23 1/3

Check:

23 1/3 * 7 + 5.5 * 11 2/3 = 227.5

163 1/3 + 64 1/6 = 227.5

163 2/6 + 64 1/6 = 227.5

227 3/6 = 227.5

227.5 = 227.5

Step-by-step explanation:

i hope write answer

step-by-step explanation:

x^2 + 81

we can factor this using difference of square binomials.

rewrite the equation:

x^2 - (-81)

factor:

(a^2 - b^2) = (√a^2 + √b^2)(√a^2 - √b^2)

(x^2 - (-81) = (x + √-81)(x - √-81)

we can remove the - from under the radical by multiplying it by i.

(x^2 - (-81) = (x + i√81)(x - i√81)

(x^2 - (-81) = (x + 9i)(x - 9i)

we can check our answer by using foil:

x^2 - 9ix + 9ix - 81i^2

x^2 - 81^2

i^2 = -1

x^2 + 81