An auditorium can seat as many as 1,200 people. The first row has 35 seats. Each of the other rows has 40 seats. What is the maximum(most) number of rows of 40 seats that can be set up in the auditorium?

29 rows of 40

Step-by-step explanation:

1200-35=1165

1165/40=29.125

answer: 2 and 1

step-by-step explanation: got this question

x=17

step-by-step explanation:

solve 3x-24=x+10

then that makes it 2x=34 because you subtract an x from both sides to get rid of the one on the right, and then you add 24 to both sides to get rid of the 24 on the left

divide by both sides by 2 to get your answer so that you can get your answer