Need a bit of help here. :/

step-by-step explanation:

graph using a few selected

x         y

-1       15

0         6

1         2.4

2       0.96

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.

(5x-1)^2= (5x)^2-2(5x)×1+(1)^2=25x^2-10x+1