Evaluate f(x)= -6+12 when x= -3,x=0, and x=1. When x= -3, f(x)= , when x=0,f(x)= , and when x=1,f(x)= .

Given :

A function, f(x) = -6 + 12

To Find :

The value of f(x) when x= -3, x= 0 and x=1.

Solution :

Given function is f(x) = -6 + 12 .

Simplifying above function, we get :

f(x) = 6

Now, the given function is independent of x.

So, for any value of x the the value of functions remains constant.

Hence, this is the required solution.

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