Given the trinomial x^2-bx-c where both the first and the second signs are negative, the signs of the factors will be:
a. cannot determine
b. both negative
c. both positive
d. one positive and one negative

Option 'D' is correct.

Step-by-step explanation:

Since we have given that

Both the first and second signs are negative,

Let α and β are the roots of the ,

then, we know that the relationship between the zeroes and coefficients of quadratic equations:

Since the product of roots is positive.

So, the signs of the factors will be one positive and one negative.

Hence, Option 'D' is correct.

$15 each

step-by-step explanation:

$45/3 children= $15 each