10+4x = 5(x−6)+ 33
solve for x

X=7

Step-by-step explanation:

10+4x=5(x-6)+33

1. Distribute the 5 to both the x and the 6

10+4x=5x-30+33

2. Subtract 4x from 5x ( should be left with 1x but just write x)

10=x-30+33

3. add 30 to both sides (whole number on the left, x on the right)

40=x+33

4. Subtract 33 on both sides

7=x (flip it around)

x=7

a) one student is chosen from classroom a, then a student is chosen from classroom b.  

step-by-step explanation:

independent events are ones in which the probability of one event does not affect the probability of the second event.

one student is chosen from classroom a; this does not affect the chances of choosing a student from classroom b.   this makes these independent events.

when one card is chosen from a standard deck and then set aside before a second card is chosen, the probability of the second card being chosen changes.   this makes them dependent events.

when one student is chosen from classroom a and then a second student is chosen from classroom a, the probability of choosing the second student changes.   this makes them dependent events.

when a letter is chosen from the alphabet and then a second letter is chosen, the probability of choosing the second letter changes.   this makes them dependent events.

56.6

step-by-step explanation:

the ratio of the perimeters is equal to the scale.

the ratio of the areas is equal to the square of the scale.

34 / 20 = k

a / 19.6 = k²

substituting:

a / 19.6 = (34 / 20)²

a = 19.6 (34 / 20)²

a ≈ 56.6