Is (x + 2) a factor of
x^3 - 4x^2 + 2x - 3?

-2x3-4x2-6x

Final result :

-2x • (x2 + 2x + 3)

Step by step solution :

Step  1  :

Equation at the end of step  1  :

((0 -  (2 • (x3))) -  22x2) -  6x

Step  2  :

Equation at the end of step  2  :

((0 -  2x3) -  22x2) -  6x

Step  3  :

Step  4  :

Pulling out like terms :

4.1     Pull out like factors :

 -2x3 - 4x2 - 6x  =   -2x • (x2 + 2x + 3)

Trying to factor by splitting the middle term

4.2     Factoring  x2 + 2x + 3

The first term is,  x2  its coefficient is  1 .

The middle term is,  +2x  its coefficient is  2 .

The last term, "the constant", is  +3

Step-1 : Multiply the coefficient of the first term by the constant   1 • 3 = 3

Step-2 : Find two factors of  3  whose sum equals the coefficient of the middle term, which is   2 .

    -3    +    -1    =    -4

    -1    +    -3    =    -4

    1    +    3    =    4

    3    +    1    =    4

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Final result :

-2x • (x2 + 2x + 3)

Step-by-step explanation:

step-by-step explanation:

option a.

step-by-step explanation:

if you look closely at the graph, we can notice that the function is not defined at two different points.

if you look at functions b and c, you will notice that both functions are not defined at just one point. the function b is not defined at x= -5/2 and function c is not defined at x=-5. both options are discarded, given that our function should not be defined at two fiferent points.

now, if you look closely at the graph you will notice that the function sketched is not defined at x=5 and x=-2.