If cosec = 13 by 12 find the value of cot+cosec

3/2 or 2/3

Step-by-step explanation:

cosec A = 13/12   (A could be in 1st or 2nd quadrant)

Cot A: positive in 1st quadrant, negative in 2nd quadrant

sin A = 12/13

cos A = ± √1 - sin² A = ± √1 - (12/13)² = ± 5/13

cot A = cos A / sin A = ±(5/13) / (12/13) = ±5/12  

cot A + cosec A = 5/12 + 13/12 = 18/12 = 3/2

or cot A + cosec A = - 5/12 + 13/12 = 8/12 = 2/3

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation: