Water SA = 2tr2 + 2nrh
(Use 3.14 for 1.)
Find the surface area
of a water tower that is
40 feet tall and 20 feet
across the base.
square feet
Do NOT round your answer.

the surface area is 3140 square feet

Step-by-step explanation:

The computation of the surface area is given below:

Given that

Diameter = 20 feet

radius =  20 ÷ 2 = 10 feet

Surface area =

= 2 × 3.14 × (10)^2 + 2 × 3.14 × 10 × 40

= 6.28  × 100  + 6.28  × 400

= 628 + 25.12  × 100

= 628+ 2512

= 3140 square feet

hence, the surface area is 3140 square feet

the final function for the graph becomes x-2=-1. before graphing you solve the equation, where x=1. then graph accordingly.   ( on the x-axis, 1 on the line will possess a vertical line.)

answer: y=4000x+14000

step-by-step explanation: