SOVing Problems With Right Triangles: Mastery Test O Submit Tes

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Type the correct answer in each box. Spell all words correctly.

Mike and Charlie are facing each other. There is a flagpole exactly halfway between them. Their line of sight to the top of the flagpole is 16 feet,.

with an angle of elevation of 60°.

Mike and Charlie both calculated the height of the flagpole as shown below.

Mike's Calculation

Charlie's Calculation

sin(60) = Height

tan(60) = Height

16

6

Height = 16 sin(60°) Height = 16 tan(60)

213.86

ft

2771 ft

Examine Mike and Charlie's calculations and complete the statement below.

The person with the incorrect reasoning for the height of the flagpole is

when he should have utilized the

.because he incorrectly selected the

function,

function.

Net)

Reset

13.86 ft

Step-by-step explanation:

This can be represented by a right angled triangle with a hypotenuse of 16 feet and an angle of 60° between the hypotenuse side and the adjacent side.

The height of the pole is the side opposite to the angle 60°.

The trigonometric function states that for a right angled triangle:

sinθ = opposite / hypotenuse, cosθ = adjacent / hypotenuse, tanθ = opposite/ adjacent

To find the height of the flagpole, we use:

sin(60) = height / 16

height = 16 * sin(60)

height = 13.86 ft

The person with the incorrect reasoning for the height of the flagpole is  Charlie when he should have utilized the  sin function. Because he incorrectly selected the  function.

a) $ 9.50

b) 17

c) y-intercept (0, 12). this is the initial amount of money that joe had prior to playing any game.

d) x-intercept ( 24, 0). this is the number of games that joe will play before he depletes the initial amount of money that he had.

e) slope is -0.5. joe's balance will reduce by 0.5 for every game that he plays.

f)

domain; [0,24]

range; [0,12]

g) x + 2y = 24

step-by-step explanation:

a)

if joe plays 5 games, this will imply that x = 5. substitute x = 5 in the equation and solve for y;

y = -.50x + 12

y = -0.50(5) + 12

y = 9.50

b)

if joe leaves the arcade with $3.50, this will mean that y = 3.50. plug in y = 3.50 in the given equation and solve for x;

y = -.50x + 12

3.50 = -0.50x + 12

0.50x = 12 - 3.50

0.5x = 8.5

x = 17

c)

the function given is   y = -.50x + 12.

the y-intercept is the point where the graph of this function will intersect the y-axis. at this point, the value of x is usually 0. plug in x = 0 in the given equation and determine y;

y = -0.50(0) + 12

y = 12

the y-intercept is thus (0, 12). this is the initial amount of money that joe had prior to playing any game.

d)

the x-intercept refers to the point where the graph of a function intersects with the x-axis. at this point, the value of y is 0. substitute y = 0 in the given equation and solve for x;

0 =   -.50x + 12

0.5x = 12

x = 24

x-intercept ( 24, 0). this is the number of games that joe will play before he depletes the initial amount of money that he had.

e)

the slope of the given equation is -0.5. the equation has been given in slope-intercept form. thus the slope is simply the coefficient of x.

joe's balance will reduce by 0.5 for every game that he plays. this is the interpretation of the slope.

f)

domain is the set of x values for which the function is real and defined. the domain will thus be; [0,24]. this will restrict the balance to only assume positive values.

on the other hand, the range is the set of y values for which a function is real and defined. the range in our case will be [0,12]. joe can have between $0 and $12 balance.

g)

the standard form of the equation of a straight line is;

ax + by = c

where a, b, and c are integers.

our equation is given as;

y = -.50x + 12

re-writing the equation we have;

0.5x + y = 12

divide all through by 0.5;

x + 2y = 24