Need answering these questions to pass

Ratio of Area of Rectangle ABEF to Rectangle ACDF is 2 : 3

Area of rectangle ABEF is 10√41 units²

Perimeter of rectangle BCDE is ( 10 + 2√41 ) units²

Step-by-step explanation:

Given: ABEF and BCDE and ACDF are rectangles.

          coordinates of F( 5 , 2 ) , E( 11 , 10 ) , D( 14 , 14 ) and A( 0 , 6 )

To find: Ratio of Area of Rectangle ABEF to Rectangle ACDF

             Area of rectangle ABEF

             Perimeter of BCDE.

We know that, Area of Rectangle = Length × Width

In rectangle ABEF

length = FE =

Width = FA

Area of Rectangle ABEF = FE × FA = ( 10 × FA ) units²

In rectangle ACDF

length = FD =

Width = FA

Area of Rectangle ACDF = FD × FA = ( 15 × FA ) units²

Thus, Ratio of Area of Rectangle ABEF to Rectangle ACDF is 2 : 3

In rectangle ABEF

length = FE = 10 units    (from above)

Width = FA =

Area of Rectangle ABEF = FE × FA = 10 × √41 = 10√41 units²

Thus, Area of rectangle ABEF is 10√41 units²

In rectangle BCDE

length = DE =  

Width = CD = FA = √41 units

Perimeter of Rectangle BCDE = 2 × ( DE + CD ) = 2 × (5 + √41) = ( 10 + 2√41 ) units²

Thus, Perimeter of rectangle BCDE is ( 10 + 2√41 ) units²

where is the figure

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

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