The sequence that proves shape I is similar to shape II when applied to shape I is a reflection across the x-axisy-axis, followed by a translation 4567 units right and 2345 units down, and then a dilation by a scale factor of

answer: 8d

step-by-step explanation:

45+5= 50+5=55+5=60

the arc length is found by finding the circumference of the full circle (2xpixradius) and then dividing by 4 to find just one quarter of the circle (90 degrees).

"standard form:

3x2 + 14x − 10 = 0

solutions based on quadratic formula:

x1   = −14 − √ 142 − 4×3×(−10) /   2×3   = −14 − 2 × √ 79 /   6   ≈ −5.296

x2   = −14 + √ 142 − 4×3×(−10) /   2×3   = −14 + 2 × √ 79 /   6   ≈ 0.629