Urgent: In a word processing document or on a separate piece of paper, use the guide to construct a two column proof proving AEC ≅ DEB, given that CA is parallel to DB and E is the midpoint of AD. Submit the entire proof to your instructor.

Given:

CA || DB

E is the midpoint of AD

Prove:

AEC ≅ DEB

AEC and DEB wouldn't be the same size because they never said that CA and DB are the same length. Therefore, it could change up the whole thing.

Step-by-step explanation:

If AC and DB were the same length, then AEC≅DEB (In Image attached. figure 1 )

BUT since you don't know that, you can't assume that they are and they would end up looking like Figure 2

So in the end, if AC and DB are the same length, then AEC ≅ DEB but if they are not, then AEC is not ≅ to DEB

proofs involving isosceles triangles often require special consideration because an isosceles triangle has several distinct properties that do not apply to normal triangles.(more about triangle types) therefore, when you are trying to prove that two triangles are congruent, and one or both triangles, are isosceles you have a few theorems that you can use to make your life easier.

step-by-step explanation:

an isosceles triangle has two congruent sides and two congruent angles. the congruent angles are called the base angles and the other angle is known as the vertex angle. ∠bac and ∠bca are the base angles of the triangle picture on the left. the vertex angle is ∠abc