What is the 72nd term of the arithmetic sequence {an}={1.4,5.5,9.6,13.7,...}

Step-by-step explanation:

Given the sequence 1.4,5.5,9.6,13.7,...

The nth term of am arithmetic sequence is expressed as;

Tn = a+(n-1)d

a is the first term

n is the number of terms

d is the common difference

From the given data;

a = 1.4

d = 5.5-1.4 = 9.6-5.5 = 4.1

n = 72 (since we are looking for the 72nd term)

Substitute;

T₇₂ = 1.4+(72-1)(4.1)

T₇₂ = 1.4+71(4.1)

T₇₂ = 1.4+291.1

T₇₂ = 292.5

Hence the 72nd term of the sequence is 292.5

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step-by-step explanation:

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step-by-step explanation: