Evaluate each function at the given value. 1) f (x) = x3 − x2 − 25x + 35 at x = −5 2) f (n) = −4n4 − 13n3 − 5n2 + 16n + 18 at n = −2

a) f(-5) =10

b) f(-2) = 26

Step-by-step explanation:

Given that the function

                 f (x) = x³ − x² − 25x + 35

Put x =-5

              f(-5) = (-5)³ - (-5)²-25(-5)+35

                    = -125-25+125+35

                   = 10

            f(-5) =10

ii)

     f(n) = -4n⁴ - 13n³-5n²+16n+18

    f(-2) = -4(-2)⁴ -13(-2)³-5(-2)²+16(-2)+18

           = -4(16)-13(-8)-5(4)-12+18

          = -64 +104-20-12+18

         = 122-96

        = 26

f(-2) = 26

step-by-step explanation: a reaction is first order. if the initial reactant concentration is 0.0200 m, and 25.0 days later the concentration is 6.25 x 10-4 m, then its half-life is:

if x = 1, then the answer is 3.5