Solve for K 2(k - 5) + 3k = k + 6

k = 4

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Equality Properties

Multiplication Property of Equality Division Property of Equality Addition Property of Equality Subtract Property of Equality

Algebra I

Terms/Coefficients

Step-by-step explanation:

Step 1: Define

2(k - 5) + 3k = k + 6

Step 2: Solve for k

Distribute 2:                               2k - 10 + 3k = k + 6Combine like terms:                  5k - 10 = k + 6Subtract k on both sides:          4k - 10 = 6Add 10 on both sides:               4k = 16Divide 4 on both sides:             k = 4

Step 3: Check

Plug in k into the original equation to verify it's a solution.

Substitute in k:                    2(4 - 5) + 3(4) = 4 + 6(Parenthesis) Subtract:       2(-1) + 3(4) = 4 + 6Multiply:                               -2 + 12 = 4 + 6Add:                                     10 = 10

Here we see that 10 does indeed equal 10.

∴ k = 4 is the solution to the equation.

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