WILL GIVE BRAINLIEST ANSWER QUICK PLZZ For a warm up, Samuel runs 200 yards less than half the maximum distance he can run. This is represented by the equation r = 1/2x-200 where x represents the maximum distance he can run and r represents the distance run during his warm up. If Samuel ran 1,600 yards during his warm up, what is the maximum distance he can run?

3,600 yards

1,600 yards

2,400 yards

1,800 yards

3,600 yards

Step-by-step explanation:

1600 + 200

=1800 ( 2/1)

1/2 x -200

        + 200

= 1/2 x (2/1)

= 3,600 =x

area of rectangle a is 2 times that of rectangle b that means 2x+x =   36cm^2

3x = 36cm ^2

x = 36/3

x= 12cm^2

and 2x = 24cm^2

now side of square = are divided by sides = 36/4 = 6cm

that means length of rectangle a and b is 6cm too

now for rectangle a,

l*b = area

= 6*y=24

y=24/6 = 4

therefore dimensions of rectangle a are- length = 6cm, breadth = 4cm

and for rectangle b, length = 6cm and breadth = 6-4 = 2cm.

hope this .