What is true about the solutions of a quadratic equation when the radicand of the quadratic formula is a perfect square?
answer

no real solutions

two identical rational solutions

two different rational solutions

two irrational solutions

The solution of quadratic formula is represented as

x = -b ± squareroot (b^2 – 4ac) / 2a

Where b^2 – 4ac is known as the radicand.

Lets take an equation; x^2 + 6x + 5 = 0

Where a = 1, b = 6, c = 5

The solution will be x = -6 ± squareroot(6^2 – 4(1)(5)) / 2(1)

Where radicand = 6^2 – 4(1)(5) = 36 – 20 = 16

Hence radicand is the perfect square of 4. i.e. 4^2 = 16

Now solving the equation further;

x = (-6 ± 4 ) / 2

x = -1 , x= -5

Thus for a radicand to be a perfect square, the solution of a quadratic equation will composed of two different rational solutions.   

one of each metals

step-by-step explanation:

not only in mathematics, scientific proof also are required in the other field of science. also maths proofs are of particular structure, containing steps and logics. so proving is like doing science, it is science. that's why it is important to prove. 

an inaccurate proof leads to errors, or stating results that are not accurate.  which wil mess the probelm up you dont want this