There are approximately, 18 men for 2 women in the armed forces. In a group of 90 military personnel, how many would you expect to be women?

10 women

Step-by-step explanation:

From the question, we are informed that there are 18 men for 2 women in the armed forces. This gives us a fraction of: 2/18 = 1/9

In a group of 90 military personnel, the number that'll be expected to be women will be:

= 1/9 × 90

= 10 women

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.

answer: 42

use a calculator to find that 845/73 = 11.575

the whole part of the answer is 11. multiply this by 73 to get 11*73 = 803.

subtract that result from 845 to get 845 - 803 = 42