A leopard is running with a velocity of 3 m/s. it then accelerates at 2 m/s² for 4 seconds. use the formula:
v = u + at
to work out the final velocity of the leopard.

please can people reply and help me thank you

Using the formula:

v = u + at

Here s is distance, u is initial velocity, v is final velocity, a is acceleration and t is time.

In this case, u = 3m/s, a = 2m/s^2, t = 4s and we want to find final velocity, v, s, v = u + at

v = 3 + 2(4) = 11m/s

Hope this helps!

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)