Douglas bought a $20 game card at a game center. The go-karts cost $3.50 each
time you race. He wants to have at least
$7.75 left on his card to play arcade games.
Write and solve an inequality to determine
how many times Douglas can race the
go-karts. Then interpret the solution.

Douglas should race 3 or fewer times to make sure he has at least $7.75 left on his card.

Given to us

Douglas bought a $20 game card at a game center.

The go-karts cost $3.50 each time you race.

Douglas wants to have at least $7.75 left on his card to play arcade games.

Assumption

Let's assume that Douglas races x number of times on go-kart.

As we know the total balance on the card is $20. And the cost of go-karts is $3.50 each time we race. Also, we need to save $7.75 on the card, therefore, Inequality can be written as,

$20 - ($3.5)x ≤ $7.75

$20 - ($3.5)x ≤ $7.75

Hence, Douglas should race 3 or fewer times to make sure he has at least $7.75 left on his card.

Learn more about Inequality:

link

Douglas can race the go-karts at least 3 times.

Step-by-step explanation:

Given that:

Worth of game card = $20

Cost of go-kart = $3.50 each time

Amount Douglas wants to left = $7.75

Let,

x be the times Douglas can ride go-kart.

20 - 3.50x ≤ 7.75

-3.50x ≤ 7.75 - 20

-3.50x ≤ -12.25

3.50x ≤ 12.25

Dividing both sides by 3.50

Hence,

Douglas can race the go-karts at least 3 times.

the solution is h=10 because you add 9 to each side of the equation.

207/8 is the right