You roll a number cube twice. Find the probability of the events. Rolling an odd number 2 or a 4.

see below

Step-by-step explanation:

If this is a 6 sided die then the only possible roll that isnt an odd, a 2, or a 4 is 6.

The probability of something happening is also the probability of something not happening. So in order to not roll an odd, a 2 or a 4 in two rolls, you have to roll a 6 twice.

P = 1 - (1/6)(1/6) = 1 - (1/36) = (35/36)

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.

1^3 + 2^3 + 3^3 +4^3 = (1+2+3+4)^2

step-by-step explanation:

i am only able to answer the first part. i am not sure about the second part. sorry