Question 13, pls help & tell how to do the problem thank u

(-4,-10) and (5,-3)

Step-by-step explanation:

To be honest, this kind of question allows for any coordinates as long as they have the slope of 9/7.

I know the slope equation is (y2-y1)/(x2-x1) = m (where m is slope)

(y2-y1)/(x2-x1) = 9/7

From this equation, find any two numbers that have a difference of 9 to the y-coordinates.

I'll go with 5 and -4 (y-coordinates)

And two integers that have a difference of 7 for the x-coordinates.

I go with -3 and -10 (x- coordinates)

So the points I got are,

(5-(-4))/((-3)-(-10)) = 9/7

5-(-4) is equal to 5+4 (2 minus signs are equal to 1 plus sign), which is 9.

(-3)-(-10) is equal to -3+10 (2 minus signs are equal to 1 plus sign), which is 7.

The two points are (-4,-10) and (5,-3)

Notice if we were to subtract 5 from -4, we would also have to subtract -3 from -10.

-4-5= -9 and -10- -3 = -10+3 = -7

-9/-7 is the same as 9/7.

Basically, (-4,-10) and (5,-3) are different coordinates and you can only switch them as coordinate 1 or 2 but not the points.

Sorry, took a while, hope I was able to help! Good Luck.

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol