6- A jeweller has nine gold figurines, from a line of high-value goods. He knows that one of these figurines weighs more than the others,
but the difference is too small to tell from looking at them.
He must use a carefully calibrated two-armed weighing scale to find
out which figurine he can sell for a higher price.
Taking care with how many you place on each side of the scales,
what is the minimum number of times in which you would have
to weigh the figurines, in order to be 100% sure which one weighs
the most?
2
4
1
3
9
5
3
10
6
7
8

i got 10.28 but that rounds up to 10.3

1. sometimes

2.   never

3   .08c = 7.50+.05c   250 pages

step-by-step explanation:

1.   sometimes

the theoretical probability of rolling a 1 is 1/6.   perhaps you got really lucky and never rolled a 1   in those 60 times.   your experimental probability is 0.   or perhaps you rolled a 1   20 times.   your experimental probability is 20/60 is 1/3.     it really just depends on how you rolled in that experiment.

2.   never

the probability of the event occurring is 1.   that is being 100 % sure it will happen.   that is the maximum amount of confidence we have.

3.   no customer card cost:   .08 times number of pages

customer card cost:   7.50 + .05 times number of pages

we want to find when it costs the same amount, so we will set these equal

let c = number of pages

.08c = 7.50+.05c

subtract .05c from each side

.08c-.05c = 7.5+.05c-.05c

.03c=7.5

divide each side by .03

.03c/.03 = 7.5/03

c =250  

the cost is the same at 250 pages

step-by-step explanation: