help me with the Quadratic equation x2+ (p - 5) x + 2q = 0 has the roots −3 and 6. Find the value of P and the value of q.

Step-by-step explanation:

The quadratic equation is x² + (p - 5)x + 2q = 0.

By Vieta's Formula,

we have SOR = -b/a and POR = c/a.

=> (-3) + (6) = -(p - 5) and (-3)(6) = 2q.

=> 3 = 5 - p and -18 = 2q

Hence, p = 2 and q = -9.

Alternate Method:

We have (x + 3) and (x - 6) as factors of the quadratic equation x² + (p - 5)x + 2q = 0.

=> (x + 3)(x - 6) = x² - 3x - 18.

By Comparing Coefficients,

(p - 5) = -3 and 2q = 18.

Hence p = 2 and q = -9.

  q

step-by-step explanation:

each line from a vertex to the midpoint of the opposite side is called a median. the point where the medians intersect, point q, is the centroid.

the centroid of δabc is point q.